Does Weighing a Floating Block Change the Combined Weight?

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SUMMARY

The discussion centers on the application of Archimedes’ principle to determine whether weighing a beaker containing a floating block of wood results in a weight measurement that is less than the sum of the individual weights of the components. The consensus is that the total weight measured will equal the sum of the weights of the beaker, water, and the floating block, as the buoyant force does not affect the overall weight in a closed system. The equation for buoyant force, fb = change in pressure * A, is relevant in understanding the forces at play but does not alter the total weight measured.

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5. A block of wood floats in a beaker of water. According to Archimedes’ principle, the block experiences an upward buoyant force. If the beaker with the water and floating block were weighed, would the measured weight be less than the sum of the weights of the individual components? Explain.



Homework Equations


fb = change in pressure * A



The Attempt at a Solution


I am utterly lost
 
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If the beaker with the water and floating block were weighed,
If block has mass m1 and beaker and water together have mass m2, what are the weights?

Now put block in the water. What happens to the masses? The what is the weight of the masses?
 
Don't laugh but my city council announced a proposal to strengthen a canal aquaduct so it could carry heavier barges!
 

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