Doppler effect and Ultrasound waves

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Ultrasound waves are utilized to measure blood flow speeds, with a scenario involving a sound emission at 450 kHz and a speed of sound in tissue at 1540 m/s. The expected beat frequency for blood flowing at 3.0 cm/s away from the source is calculated using the Doppler Effect formula. There was confusion regarding the correct formula, with one participant mistakenly using an incorrect version. The correct approach involves calculating the frequency of beats based on the Doppler shift, leading to a final calculation that incorporates the given values. This discussion emphasizes the importance of using the correct formulas in Doppler Effect problems.
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Homework Statement



Ultrasound waves are used to measure blood-flow speeds. Suppose a device emits sound at 450 kHz, and the speed of sound in human tissue is taken to be 1540 m/s. What is the expected beat frequency if blood is flowing normally in large leg arteries at 3.0 cm/s directly away from the sound source?
_____Hz

Homework Equations



F2 = F1 / ( 1 + ( Vs / V ) )

The Attempt at a Solution



F2 = 450000 / (1 + ( 1540 / 343 ) )
F2 = 81970.26 Hz
 
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F2 = F1 / ( 1 + ( Vs / V ) )
Your formula is wrongIt should be F2 = F1/[1 + v/vs] and what is 343?
 
rl.bhat said:
F2 = F1 / ( 1 + ( Vs / V ) )
Your formula is wrongIt should be F2 = F1/[1 + v/vs] and what is 343?

I am a bit confused. The OP has used the correct formula for the Doppler Effect for moving source. However, the formula given by you is the correct formula for the beat frequency.

To help the OP, I'll just give a short deduction.

f1 = f/(1 + vs/v) = fv/(v+vs), where v = speed of sound = 1540 m/s, f = 450 kHz, vs = 0.03 m/s.

Frequency of beats = f –f1 = f(1 – v/(v+vs) = f*vs/(v+vs) ~ f*vs/v, since v>>vs.

Now plug in the values.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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