What is the Formula for the Doppler Effect?

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The Doppler Effect describes the change in frequency or wavelength of a wave in relation to an observer moving relative to the source of the wave. The formulas for the Doppler Effect include variations for a moving observer, moving source, and both moving observer and source. For a moving observer, the formula is F = (1 ± (u/v))f, while for a moving source, it is F = (1/(1 ± (u/v)))f. When both the source and observer are in motion, the formula combines these variables. The discussion also touches on the implications of relativistic effects at high velocities, noting the phenomena of redshift and blueshift based on the direction of movement.
Blueice88
Hi All... Who knows the formula of the Dopler´s Effect??Please someone help me.This is a little curiosity that I Have.Regards.




BlueIce88
 
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DOPPLER EFFECT FOR MOVING OBSERVER:

F = (1+ OR 1-(U/V))f

Units are inversed seconds

v = speed of wave
u = speed of observer
F = with doppler effect
f = without doppler effect

I just got this outta my old physics book as we didn't cover this chapter so it's as new to me as to you!
 
DOPPLER EFFECT FOR MOVING SOURCE:

F = ((1)/(1+ or 1-(U/V)))f

Same units as above
Same variable definitions as above



DOPPLER EFFECT FOR MOVING SOURCE AND MOVING OBSERVER

F = ((1+ or 1-(u/v))/(1+ or 1-(U/V)))f

Same units as above
Addition variables:

u = moving observer
U = moving source
 
Relativistic transformation given by [squ](1 + v/c) / [squ](1 - v/c) if you want that one for high velocities.

Wavelength is red-shifted (lengthened), and frequency shortened for sources moving away. Blue-shift/longer frequency for sources moving towards observer.
 
Yeah mulder. Interesting I didn't see these relativistic equations in the relativity chapter...

The low note on a bass guitar, traveling at the speed of light, ouch that might hurt my ears!
 
Thank You... Very Much friends! I´m Glad to be part of this forum!Regards.


[]´s


BlueIce88
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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