1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Doppler effect Indianapolis 500 problem

  1. Apr 7, 2007 #1
    1. The problem statement, all variables and given/known data

    At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise between approaching and receding cars. Suppose the sound of a certain car drops by a factor of 1.50 as it goes by on the straightaway. How fast is it going? (Take the speed of sound to be 343 m/s.)

    answer given in km/h

    2. Relevant equations

    v= (1- (f/(f prime/1.5))v

    where the second v is the speed of sound.

    Sorry it isnt a cleaner equation, I couldn't figure out how to get my mathtype equation from microsoft word here.

    3. The attempt at a solution
    The equation above is my attempt at a solution, since the sound of the cars frequency drops by 1.5 thats what I divided my f prime by. I just dont know how to figure out the f values. Maybe I am using the wrong equation, I just can't figure out any other way to solve for the speed of the car. Any hints would be greatly appreciated and I thank you for your time.
  2. jcsd
  3. Apr 7, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper

    1.5 IS f/f'. You don't need to know the values of f.
  4. Apr 7, 2007 #3


    User Avatar
    Science Advisor
    Homework Helper

    And be careful. When the car is coming toward you it's doppler shifted up in pitch and when it leaves you it is shifted down. As I read the question there is a factor of 1.5 between the ratios of those two pitches.
  5. Apr 7, 2007 #4


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Welcome to the forums!

    I don't quite see how you got your equation but I have a feeling that you used incorrectly the factor of 1.5.

    Set up an equation for the frequency of the sound when the car is going toward you. Call this frequency [itex] f^' [/itex]. It will contain the frequency emitted by the source that I will call [itex] f_{source} [/itex] to be clear. Now find an expression for the frequency when the car is moving away from you. Let's call this f double prime = [itex] f^{''}[/itex].

    What they are telling you is that [itex] \frac{f^'}{f^{''}} = 1.5 [/itex]. So take the ratio of your two equations and you will see that [itex] f_{source}[/itex] will drop out, leaving you with an equation for the speed of the source (the car) in terms of the speed of sound.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Doppler effect Indianapolis 500 problem
  1. Doppler effect problem (Replies: 2)

  2. Doppler Effect Problem (Replies: 1)

  3. Doppler Effect Problem (Replies: 8)

  4. Doppler effect problem (Replies: 6)