What is the distance traveled by a rollercoaster based on the Doppler effect?

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The discussion centers on calculating the distance traveled by a rollercoaster using the Doppler effect, where the pitch of screams from riders increases by 30% as they approach. Participants emphasize the need to apply the Doppler shift equation to determine the source velocity. Key variables include the observed frequency, emitted frequency, and the speed of sound. The problem involves algebraic manipulation to derive the rollercoaster's movement distance based on the time it takes to come to a stop. Ultimately, the original poster successfully solved the problem after collaborating with others.
starhallie
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Homework Statement



Standing in line next to the scariest rollercoaster of all time, you see your friends screaming their heads off as they come speeding out of the end of the ride. The sound of their screams is about 30% higher in pitch than normal due to the Doppler shift caused by their motion towards you. If they sound normal again by the time the rollercoaster has halted about 1.5 seconds later, estimate how far the rollercoaster moved as it was coming to rest.

Homework Equations



f(observed)= f(emitted)((v(sound) +/- v(observer)/(v(sound) +/- v(source))

The Attempt at a Solution



My hunch on this problem is that I need to create some sort of ratio with the 30% given in the problem in order to solve it, and I know I'll have to do some algebra to get a velocity for my final answer. Would anyone be willing to brainstorm this with me? I'd really appreciate it!
 
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starhallie said:

Homework Equations



f(observed)= f(emitted)((v(sound) +/- v(observer)/(v(sound) +/- v(source))

Yes, you'll need to use this equation to find v(source). Some other information to use:

What is v(observer)?
What's another relation between f(observed) and f(emitted), using the information given in the problem statement?
 
Thank you for the help. I ended up figuring it out!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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