Dot product between grad f and an arbitrary vector

Click For Summary
The discussion centers on whether the dot product of the gradient of a function f and an arbitrary vector v at a point x is equivalent to the directional derivative df/dv. It is clarified that the dot product represents the rate of change of f in the direction of v, scaled by the length of v. The directional derivative, denoted as Dv f, specifically measures the change in f in the direction of a unit vector. The distinction is made that one cannot differentiate with respect to a vector, emphasizing the need to define df/dv properly. Overall, the relationship between the gradient, dot product, and directional derivative is elucidated, enhancing understanding of these concepts.
guiness
Messages
4
Reaction score
0
Given a function f: R^n -> R, a point x in R^n, and an arbitrary vector v in R^n - is the dot product between grad f and v (evaluated at x) the same as df/dv?

If yes, it would be great if someone were to demonstrate a proof.

If no, what should be the correct interpretation of the dot product?
 
Physics news on Phys.org
The first thing you will have to do is define df/dv! I know, for example, Dvf as the directional derivative Defennder refers to- the rate of change of f in the direction of v which is independent of the length of v. The dot product of grad f with an arbitrary unit vector is the derivative in that direction. The dot product of grad f with an arbitrary vector is the derivative in that direction multiplied by the length of the vector.
 
Thanks for the links! It makes sense now.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 20 ·
Replies
20
Views
7K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
1
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K