Ted123 Messages 428 Reaction score 0 Thread starter Nov 30, 2011 #1 I need to get from [tex]\cosh^2(v)-2\cos(u)\cosh(v) + 4\cos^2(\frac{u}{2})\sinh^2(\frac{v}{2}) + 1[/tex] to [tex](1+\cosh(v))(\cosh(v)-\cos(u))[/tex] using double angle formulae.
I need to get from [tex]\cosh^2(v)-2\cos(u)\cosh(v) + 4\cos^2(\frac{u}{2})\sinh^2(\frac{v}{2}) + 1[/tex] to [tex](1+\cosh(v))(\cosh(v)-\cos(u))[/tex] using double angle formulae.
susskind_leon Messages 177 Reaction score 0 Nov 30, 2011 #2 Turn the double angle formulae into half-angle formulae, then it should be a piece of cake.