Double-Angle Formula: Solving for (1+\cosh(v))(\cosh(v)-\cos(u))

  • Thread starter Thread starter Ted123
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary
SUMMARY

The discussion focuses on transforming the expression \(\cosh^2(v)-2\cos(u)\cosh(v) + 4\cos^2(\frac{u}{2})\sinh^2(\frac{v}{2}) + 1\) into the form \((1+\cosh(v))(\cosh(v)-\cos(u))\) using double-angle and half-angle formulas. The key techniques involve applying hyperbolic identities and simplifying the terms systematically. The transformation is essential for solving equations involving hyperbolic functions and trigonometric identities.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically \(\cosh\) and \(\sinh\)
  • Familiarity with double-angle and half-angle formulas in trigonometry
  • Basic algebraic manipulation skills
  • Knowledge of trigonometric identities, particularly for cosine
NEXT STEPS
  • Study hyperbolic function identities and their properties
  • Learn about the derivation and application of double-angle formulas
  • Explore half-angle formulas and their uses in simplifying expressions
  • Practice algebraic manipulation of trigonometric and hyperbolic expressions
USEFUL FOR

Mathematicians, physics students, and anyone working with hyperbolic functions and trigonometric identities in problem-solving contexts.

Ted123
Messages
428
Reaction score
0
I need to get from [tex]\cosh^2(v)-2\cos(u)\cosh(v) + 4\cos^2(\frac{u}{2})\sinh^2(\frac{v}{2}) + 1[/tex] to [tex](1+\cosh(v))(\cosh(v)-\cos(u))[/tex] using double angle formulae.
 
Physics news on Phys.org
Turn the double angle formulae into half-angle formulae, then it should be a piece of cake.
 

Similar threads

Replies
2
Views
1K
Replies
32
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
9
Views
2K
Replies
4
Views
2K