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veronicak5678
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Hoping someone could double-check for me...
1) A 90 g block of unknown metal is heated to 86 degrees C and put in an insulated cup with 175 g water at 23 degrees C. At equilibrium, they are both 25.8 degrees C. What is the specific heat of the metal block?
2) A well insulated cup contains 145 g of ice at 0 degrees C. We pour in 45 g watwer at 75 degrees C.
a- Once equilibrium is established, how many grams of ice remain?
b- What is the final temp in the cup?
1) c ( 90 g) (-60.2 degrees c) + 1 cal/g degrees C) (175 g) (2.8degrees C) = 0
c = 0.0904 cal/g degree C
2)
a- energy available to melt ice: 1 cal/ g celsius (45 g) ( 75 degrees ) = 3375 cal
energy needed to melt ice: 145 g (80 cal/g) = 11600 cal
not all will melt
80 cal /g (mass melted) = 3375 cal
mass melted = 42.19 g
b- Temp is 0 since there is still ice.
Homework Statement
1) A 90 g block of unknown metal is heated to 86 degrees C and put in an insulated cup with 175 g water at 23 degrees C. At equilibrium, they are both 25.8 degrees C. What is the specific heat of the metal block?
2) A well insulated cup contains 145 g of ice at 0 degrees C. We pour in 45 g watwer at 75 degrees C.
a- Once equilibrium is established, how many grams of ice remain?
b- What is the final temp in the cup?
The Attempt at a Solution
1) c ( 90 g) (-60.2 degrees c) + 1 cal/g degrees C) (175 g) (2.8degrees C) = 0
c = 0.0904 cal/g degree C
2)
a- energy available to melt ice: 1 cal/ g celsius (45 g) ( 75 degrees ) = 3375 cal
energy needed to melt ice: 145 g (80 cal/g) = 11600 cal
not all will melt
80 cal /g (mass melted) = 3375 cal
mass melted = 42.19 g
b- Temp is 0 since there is still ice.