A researcher studies the heat transference between an iron block and an unknown substance, inside an adiabatic calorimeter. In successive experiences he puts inside the calorimeter the unknown substance, always in its solid state and with temperature θs = 20ºC, and the iron block, in each case with a different initial temperature "θi". In each case he measures the equilibrium temperature "θe". The results are shown in the graphic.
The quotient of the mass of the iron block and the mass of the unknown substance, "mi/ms", is equal to 0,8.
Consider the specific heat of the iron = 0.1 cal/g ºC
Question: Find the specific heat, "cs", of the unknown substance in its solid state
Q = m c Δθ
3. The Attempt at a Solution
Let mi = mass of the iron block; ms = mass of the substance; cs = specific heat of the substance; ci = specific heat of the iron; θe = the equilibrium temperature; θi = the initial temperature of the iron block; θs = the initial temperature of the substance
The process is thermally isolated, so Q received = Q given ⇒ [(ms)(cs)(θe - θs)] = [(mi)(ci)(θe-θi)] ⇒
mi/ms is constant = 0,8; θs = 20 and ci = 0,1 ⇒ (cs)(θe - θs) = 0,08(θe-θi) ⇔ cs = 0,08(θe-θi)/(θe - 20)
So, here's the problem. In the graph I initially picked the (150;50) point because it gives me the easy 100, so the cs = 4/15 cal/g ºC, but upon checking online the only answer I found (albeit not in a truly trustworthy source) is 0,28 cal/g ºC. Getting back to the exercise, this is the answer that we get when we input (200;60). (150;50) = 4/15 cal/g ºC; (100;40) = 0,24 cal/g ºC; (50;30) = 0,16 cal/g ºC.
My forced conclusion here is that the specific heat of the substance in its solid state is not constant (because the question did say the iron one was constant). So how should I know that the correct one was the (200;60)? Is my conclusion that cs is not a constant correct?
PS: Just to be sure, in the graph of the image, the Y axis are the equilibrium temperatures, the X - axis are the different temperatures of the iron block.
PS2: This is from an acceptance exam from 1997 and there are no definitive solutions of this online, so, again, I'm not entirely sure about the 0,28 cal/ g ºC
PS3: I wasn't able to host the image for some reason, in the preview it never showed up.
PS4: I'm sorry if I broke any rule, it's my first time posting.