Double integration of an exp function

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Homework Help Overview

The original poster attempts to find the area under the curve of the function e^(-x^2) within a specified domain involving the variables x and y. The problem is situated within the context of double integration.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts at setting up the double integral and integrating with respect to different variables. Questions arise regarding the correctness of initial integration steps and the potential use of substitution methods. Some participants suggest evaluating the integral from different limits and switching the order of integration.

Discussion Status

The discussion is ongoing, with participants providing guidance on integration techniques and exploring different approaches. There is no explicit consensus, but several productive lines of reasoning are being examined.

Contextual Notes

Participants note that the integral of e^(-x^2) does not have a solution in terms of elementary functions, which introduces complexity into the evaluation process. The original poster expresses some confusion regarding the integration limits and the evaluation of the integral.

Vandella
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Homework Statement





Please help I need to find the area of e^(-x^2) with the domain 0 is less than or equal to y which is less than or equal to 1 and y is less than or equal to x which is less than or equal to one

Homework Equations





The Attempt at a Solution


I set up the equation ∫ ∫ e^(-x^2) dydx with values y=x and y=0 and x=1 and x=0
attempted to integrate but struggling.
 
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Let's see your attempt at integration then
 
Well I started by integrating with respect to y and got ye^(-x^2)dx,I then solved for the values y=x and y=0 leaving xe^(-x^2)dx and unsure of if my first steps are correct and how to continue.
My idea for a next step would be integration by substitution u=-x^2 but unsure as to whether that would work
 
why -x^2?
I'd just go for x^2

Try it and see what happens
 
Ok here goes u= x^2 that gives ∫ e^(-u) integration by substitution gives me -(e^x^2)/2
Possibly :)

Now do I just solve for x=1 and x=y?
 
When you did your first integration, you essentially integrated the strip from 0 to y=x, in the second integration you are taking all of those strips from 0 to 1, you don't need to solve for x=1 or x=y, you just need to evaluate the integral from 0 to 1
 
Sorry when I said solve I meant evaluate.
Could I switch the order of integration so when I evaluate after integrating a second time I lose x and y from the equation?
 
Try it and see what happens
You'll have trouble evaluating it if you do the dx integration first however, the integral of e^(-x^2)dx isn't nice, it isn't solvable in terms of elementary functions. If you're interested, the name of the solution is the error function.
 
Thanks for your help will just leave it now and not confuse myself even more
 
  • #10
Vandella said:
Thanks for your help will just leave it now and not confuse myself even more

The best way to get use to it is to just play about with it and see what you end up with.
 

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