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Answer in Book: 12nm

my problem: the formula i thought you would use is sin(theta) = m(wavelength)/d?? However you do not know an angle? any ideas??

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- Thread starter SwAnK
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- #1

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Answer in Book: 12nm

my problem: the formula i thought you would use is sin(theta) = m(wavelength)/d?? However you do not know an angle? any ideas??

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Päällikkö

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Of course [tex]-\frac{\pi}{2} < \theta < \frac{\pi}{2}[/tex]. Can you solve it now?

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- #4

Päällikkö

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[tex]\lambda _{max} \approx d[/tex]

Which according to your book is wrong. I'm stunned. I suppose the answer in the book is wrong: they've forgotten the zeros.

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