DOUBLE slit interference experiment

Click For Summary
The double slit interference experiment shows a fringe pattern when light passes through two slits, creating alternating dark and light bands on a screen. Immersing the apparatus in water alters the fringe pattern due to the change in the speed of light in water compared to air. The key formula for fringe separation involves the wavelength of light, which decreases in water, affecting the spacing of the fringes. Participants suggest posting initial thoughts for better assistance and recommend resources like HyperPhysics for further information. Understanding the impact of the medium on wave behavior is crucial for solving this problem.
ah lai
Messages
5
Reaction score
0
the double slit interference experiment is set up and the fringes are displayed on screen. Then the whole apparatus is immersed in the nearest swimming pool. How does the fringe pattern change?? Which website I can get information?? Thanks.
 
Physics news on Phys.org
This is a homework problem correct? (I believe I have seen it on mastering physics.)

First, if you post your thoughts on the problem to show you have made some effort you can get help in the homework help forms here. Also, if you want a good website for summaries of intro physics topics you can try:

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
 
No, it's past yr question. I dun understand wat question is ? no idea.. I oledi tried to search information on internet.. still can't get it...

when the whole apparatus place on the table, dark & light pattern display on the screen if using light source.

do u think the whole apparatus including light source is immersed in the water? or using other source?
 
picture it this way, instead of doing the experiment in air, you are doing it in water.

what is the formula concerning the fringe separation? which of the parameters in it changes when the wave is traveling in water and not in air?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 23 ·
Replies
23
Views
2K
Replies
3
Views
6K
  • · Replies 7 ·
Replies
7
Views
646
  • · Replies 1 ·
Replies
1
Views
3K