Double Slit Problem: Solve for D2-D1 with 500nm Wavelength

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SUMMARY

The discussion centers on solving for the distance difference (D2-D1) in the Young Double Slit experiment using a light wavelength of 500nm. The problem highlights that one slit is closer than the other, leading to the formation of alternating bright and dark bands on the screen. The relationship between the distance between slit centers (d) and the angle (θ) is defined by the equation mλ = d sin θ, where m represents the order of the fringe. The absence of specific measurements complicates the calculation, necessitating further information for precise resolution.

PREREQUISITES
  • Understanding of the Young Double Slit experiment
  • Familiarity with wave interference patterns
  • Knowledge of the equation mλ = d sin θ
  • Basic principles of light wavelength measurement
NEXT STEPS
  • Research the derivation of the Young Double Slit experiment equations
  • Learn about fringe spacing and its dependence on slit separation
  • Explore the impact of wavelength on interference patterns
  • Investigate methods for measuring angles in optical experiments
USEFUL FOR

Physics students, educators, and researchers interested in wave optics and the principles of interference in light. This discussion is particularly beneficial for those studying the Young Double Slit experiment and its applications in understanding wave behavior.

knox_122
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here the problem:

In the Young Double Slit experiment, alternatingbands of bright and dark regions are produced on the screen. At the dark band shown in the picture below, on slit is a closer than the other slit: In other words, D1 is less than D2, Find D2-D1, Assuming that the light has a wavelength of 500nm.


The Picture he shows, he said is not to scale so it won't help. there are no other measurements listed. How do i go about figuering this out?
 
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I hope there's an angle scale in the pic.

Distance between slit centers "d" makes fringes (bands) that are angle-dependent, as m \lambda = d sin \theta
 

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