Double & Triple Integrals: Same Solution?

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SUMMARY

In the context of double and triple integrals, the order of integration does not affect the final result, provided that the integral boundaries are correctly established and that an antiderivative can be found for the integrand. This principle holds true for integrals such as $\int_{0}^{2} \, \int_{0}^{4} \, \int_{1}^{2} \ NHN \, dy \, dx \, dz$ and $\int_{0}^{4} \, \int_{0}^{2} \, \int_{1}^{2} \ NHN \, dx \, dy \, dz$, which yield the same outcome. Understanding how to reverse the order of integration is crucial for solving integrals where direct computation may not be feasible.

PREREQUISITES
  • Understanding of double and triple integrals
  • Knowledge of integral boundaries and their setup
  • Familiarity with antiderivatives and integrands
  • Ability to reverse the order of integration
NEXT STEPS
  • Study the properties of double and triple integrals
  • Learn techniques for changing the order of integration
  • Explore examples of integrals with complex boundaries
  • Practice finding antiderivatives for various integrands
USEFUL FOR

Students and professionals in mathematics, particularly those studying calculus, as well as educators teaching integral calculus concepts.

ineedhelpnow
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when taking double or triple integrals, do you get the same solution no matter which variable you integrate with respect to first?
 
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ineedhelpnow said:
when taking double or triple integrals, do you get the same solution no matter which variable you integrate with respect to first?

You have asked a fat question there. You will get the same solution no matter what order you choose to integrate the variables in as long as you have set up the integral boundaries in each case, and as long as it is possible to find an antiderivative of the integrand in each way (sometimes you can't, which is why it is important to know how to reverse the order of integration).
 
what do you mean by how to reverse the order of the integrand? say if you have like $\int_{0}^{2} \, \int_{0}^{4} \, \int_{1}^{2} \ NHN, dy dx dz$ , that would be the same as $\int_{0}^{4} \, \int_{0}^{2} \, \int_{1}^{2} \ NHN, dx dy dz$, right?a fat question? (Wondering)
 

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