So when finding the Area from a double integral; or Volume from a triple integral: If the curve/surface has a negative region: (for areas, under the x axis), (for volumes, below z = 0 where z is negative)(adsbygoogle = window.adsbygoogle || []).push({});

What circumstances allow the negative regions to be taken into account as positive when finding the area/volume without having to split the integral up and add a negative piece to it?

Does polar form specifically allow for this since r can not be negative? Or is a double integral for area, triple integral for volume sufficient for this regardless of the coordinate system used since they are the same dimensionality as the scalar in question? Or they all have to be split up in order to calculate the negative area/volume correctly regardless of which coordinate system we're using?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# I Q about finding area with double/volume with triple integral

Have something to add?

Draft saved
Draft deleted

Loading...

Similar Threads for finding area double | Date |
---|---|

Finding area in polar coordinates | Jan 21, 2015 |

Find the line that gives constant area in odd shape | Nov 20, 2012 |

Trying to find the area between two curves | Oct 15, 2012 |

Double integral to find the area of the region enclosed by the curve | Apr 10, 2005 |

Help Finding Surface area with Double Integrals. (work shown) | Apr 5, 2004 |

**Physics Forums - The Fusion of Science and Community**