So when finding the Area from a double integral; or Volume from a triple integral: If the curve/surface has a negative region: (for areas, under the x axis), (for volumes, below z = 0 where z is negative)(adsbygoogle = window.adsbygoogle || []).push({});

What circumstances allow the negative regions to be taken into account as positive when finding the area/volume without having to split the integral up and add a negative piece to it?

Does polar form specifically allow for this since r can not be negative? Or is a double integral for area, triple integral for volume sufficient for this regardless of the coordinate system used since they are the same dimensionality as the scalar in question? Or they all have to be split up in order to calculate the negative area/volume correctly regardless of which coordinate system we're using?

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# I Q about finding area with double/volume with triple integral

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