1. The problem statement, all variables and given/known data A light bulb is designed for use in a 120 V circuit. If by mistake it is plugged into a 240 V circuit, what will happen to the power of the light bulb? Explain. 2. Relevant equations I = V/R P = VI 3. The attempt at a solution Since I = V/R and the resistance of the lightbulb does not change, doubling V also doubles I. Pf = 2V2I = 4P0. Alternatively, P = V2/R, so doubling V quadruples P. Where I'm getting stuck is on explaining this. What are the practical implications of quadrupling the power? What is the physical representation of quadrupling it - I mean, aside from the equations, WHY is it quadrupled? I'm really stuck on this.