Draw a Parallelogram: Step-by-Step Guide

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SUMMARY

This discussion provides a step-by-step guide for drawing a parallelogram with specific dimensions: side length a = 4cm, the sum of diagonals e + f = 11cm, and an angle of 22° between side a and diagonal e. Key geometric principles highlighted include the properties of parallel sides and the behavior of diagonals, which bisect each other. The discussion also addresses the implications of changing side length a to 8cm, emphasizing that a must not exceed half the sum of the diagonals for the triangle to exist.

PREREQUISITES
  • Understanding of basic geometric properties, specifically parallelograms
  • Knowledge of triangle properties, particularly isosceles triangles
  • Familiarity with geometric constructions using perpendicular bisectors
  • Ability to interpret and apply geometric equations
NEXT STEPS
  • Study the properties of parallelograms and their diagonals
  • Learn about geometric constructions using compass and straightedge
  • Explore the implications of triangle inequality in geometric figures
  • Practice drawing various types of triangles and parallelograms with different dimensions
USEFUL FOR

Students studying geometry, educators teaching geometric principles, and anyone interested in improving their skills in geometric constructions and problem-solving.

Redinorun
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I'd really need help with this. Thanks.

1. Homework Statement

Draw a parallelogram:
a = 4cm
e + f (diagonals) = 11cm
angle between a and e = 22°

Homework Equations


2 and 2 sides are parallel
both diagonals halve each other
(diagonal e goes from A to C)

The Attempt at a Solution


(attachment)
 

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  • Paralelogram.png
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Go ahead with your attempt! You have drawn the blue triangle. PRS is isosceles. Halve the side RS and draw a perpendicular at the halfpoint. It defines point P.

ehild
parallelogram.JPG
 
ehild said:
Go ahead with your attempt! You have drawn the blue triangle. PRS is isosceles. Halve the side RS and draw a perpendicular at the halfpoint. It defines point P.

ehild
View attachment 74044

Thanks, got it. You're a life saver. By the way: Why wouldn't this work if a = 8cm? Is it because a would be longer than the sum of e and b (if we take half of it as a triangle)? Or is there another explanation?
 
a can not be longer than (e+f)/2. The yellow triangle would not exist.

paral.JPG
 
ehild said:
a can not be longer than (e+f)/2. The yellow triangle would not exist.

View attachment 74049

Thank you! (I menth something like that, yes)
 

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