Drawing Complex Numbers on a Plane

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SUMMARY

The discussion focuses on plotting complex numbers on a plane, specifically the calculations for four complex numbers: \(z_{1}=\frac{2}{i-1}\), \(z_{2}=-\bar{z_{1}}\), \(z_{3}=\bar{z_{2}}\), and \(z_{4}=\frac{z_{3}}{i}\). The rationalization of the denominator for \(z_{1}\) is demonstrated, resulting in \(z_{1} = -i + 1\). The participants engage in clarifying the results and confirming the calculations, particularly for \(z_{2}\) as \(-1-i\).

PREREQUISITES
  • Understanding of complex numbers and their representation on a Cartesian plane
  • Knowledge of complex conjugates and their properties
  • Familiarity with rationalizing denominators in complex arithmetic
  • Basic skills in algebraic manipulation of complex expressions
NEXT STEPS
  • Explore the geometric interpretation of complex numbers on the Argand plane
  • Learn about transformations of complex numbers, including rotations and scalings
  • Investigate the properties of complex conjugates and their applications
  • Study the use of complex numbers in signal processing and electrical engineering
USEFUL FOR

Students of mathematics, educators teaching complex analysis, and professionals in engineering fields who utilize complex numbers in their work.

Yankel
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Hello all,

I wish to plot and following complex numbers on a plane, and to find out which shape will be created. I find it hard to figure out the first one, I believe that the others will follow more easily (the forth is also tricky).

\[z_{1}=\frac{2}{i-1}\]

\[z_{2}=-\bar{z_{1}}\]

\[z_{3}=\bar{z_{2}}\]

\[z_{4}=\frac{z_{3}}{i}\]

Thank you !
 
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"Rationalize the denominator": [math]\frac{2}{i- 1}= \frac{2}{i- 1}\frac{-i- 1}{-i- 1}= \frac{2(-i- 1)}{(-1)^2+ 1}= \frac{-2i- 2}{2}= -i+ 1[/math]
 
HallsofIvy said:
"Rationalize the denominator": [math]\frac{2}{i- 1}= \frac{2}{i- 1}\frac{-i- 1}{-i- 1}= \frac{2(-i- 1)}{(-1)^2+ 1}= \frac{-2i- 2}{2}= -i+ 1[/math]

you mean -1-i ?

thanks !
 

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