- #1

integrash

- 1

- 0

length of wire 1m for 10V

cross sectional area = 0.001m^2

e = 1.602 x 10^-19

ue = 3.18 x 10^-7

n = 10^23 electrons / m^3

what does ue stand for?

how do i calculate drift verlocity?

3. The Attempt at a Solution

i am using the formula

I = nAVq

where I = current

n = number of charged particles per unit volume (10^23)??

A = cross sectional area (0.001)

V = drift verlocity

drift verlocity = ue (3.18 x 10^-7) x charge dencity (charge dencity = 10^23 x 1.602 x 10^-19)

Q = charge on each particle (1.602 x 10^-19)

therefore

I = (10^23) x (0.001) x (3.18 x 10^-7 x 10^23 x 1.602 x 10^-19) x (1.602 x 10^-19)

I = 0.08161 A

or 81.61 mA

No idea if any of this is correct please help

Many thanks

Rob.