well,the formula of the dynamic head is"H=P/W",where p:pressure&W:specific weight=density*acceleration"g",of the fluid passing in the tube.
u can apply the bernouli's equation as russ watters mentioned in his reply,between two points,say point"1" at the surface of the tube and at point"2" at the centre of the tube&at the centre line of the 1st two holes,and I've noticed that the every two holes at the same horizontal line?,their centre line is at the same line?,
so by using bernouli's:
(P1/W1+Z1+V1^2/2g)-(P2/W2+Z2+V2^2/2g)=head lossed from point "1" to point "2".
and according to my assumptions:taking the datumn at the holes centre line: Z1=the distance from point"1"to point"2"&Z2=0.0,
according to ur givens u should calculate the head losses in the pipe by adding the head losses calculated everytime between the every two points.
notice that the head losses formula is : "hl=flv^2/2gd" ,or "hl=0.8flq^2/gd^5" , where f:friction factor,l:tube length,v:fluid velocity in the tube,d:tube daimeter,q:fluid flow rate.
and for the pressure drop:
H1-H2=deltaP1>>2
H1-H3=deltaP1>>3
H1-4=deltaP1>>4.
hope this help.
thanks.