Dynamic head, pressure drop formulas?

AI Thread Summary
To calculate dynamic head in a tube, use the formula H = P/W, where P is pressure and W is the specific weight of the fluid. Bernoulli's equation can be applied between two points in the flow to assess head loss, factoring in pressure, elevation, and velocity changes. The head loss can be calculated using formulas such as hl = flv^2/2gd or hl = 0.8flq^2/gd^5, where f is the friction factor, l is tube length, v is fluid velocity, d is tube diameter, and q is fluid flow rate. For pressure drop calculations, differences in head between points can be expressed as H1 - H2 = deltaP1. Online resources like eFunda.com provide additional theoretical information and calculators for fluid mechanics.
engineering
Messages
12
Reaction score
0
My fluid dynamics is rather weak and i was wondering if someone could please tell me how to calculate dynamic head of the flow in the a tube and how to calculate pressure drop of a hole in a tube? Some formulas would be handy



thanks



engineering
 
Engineering news on Phys.org
Generally, you just use a table for certain materials and velocities. IIRC, we use a book put out by BOCA. And I'm not sure what you mean by a hole in the tube - an orifice?
 
Please see my diagram the diameters of the hold are fixed it has a fluid running through it being injected outwards. The diameter of the holes is fixed. the tube shape chamber has a free stream velocity flowing round it can be assumed to be air. need method of calculating pressure drop and head loss.
 

Attachments

I'm still not completely clear on it, but if you have a certain flow rate through the holes in mind, you can use bernoulli's equation to calculate the pressure required to get it. Figure on a 50% nozzle coefficient (meaning whatever pressure you get, double it).
 
well,the formula of the dynamic head is"H=P/W",where p:pressure&W:specific weight=density*acceleration"g",of the fluid passing in the tube.
u can apply the bernouli's equation as russ watters mentioned in his reply,between two points,say point"1" at the surface of the tube and at point"2" at the centre of the tube&at the centre line of the 1st two holes,and I've noticed that the every two holes at the same horizontal line?,their centre line is at the same line?,
so by using bernouli's:
(P1/W1+Z1+V1^2/2g)-(P2/W2+Z2+V2^2/2g)=head lossed from point "1" to point "2".
and according to my assumptions:taking the datumn at the holes centre line: Z1=the distance from point"1"to point"2"&Z2=0.0,
according to ur givens u should calculate the head losses in the pipe by adding the head losses calculated everytime between the every two points.
notice that the head losses formula is : "hl=flv^2/2gd" ,or "hl=0.8flq^2/gd^5" , where f:friction factor,l:tube length,v:fluid velocity in the tube,d:tube daimeter,q:fluid flow rate.
and for the pressure drop:
H1-H2=deltaP1>>2
H1-H3=deltaP1>>3
H1-4=deltaP1>>4.
hope this help.
thanks.
 
Hi there:

Check out eFunda.com at: http://www.efunda.com where you can find theoretical background information as well as online calculators on fluid mechanics.

Thanks,

Gordan
 
I need some assistance with calculating hp requirements for moving a load. - The 4000lb load is resting on ball bearing rails so friction is effectively zero and will be covered by my added power contingencies. Load: 4000lbs Distance to travel: 10 meters. Time to Travel: 7.5 seconds Need to accelerate the load from a stop to a nominal speed then decelerate coming to a stop. My power delivery method will be a gearmotor driving a gear rack. - I suspect the pinion gear to be about 3-4in in...
How did you find PF?: Via Google search Hi, I have a vessel I 3D printed to investigate single bubble rise. The vessel has a 4 mm gap separated by acrylic panels. This is essentially my viewing chamber where I can record the bubble motion. The vessel is open to atmosphere. The bubble generation mechanism is composed of a syringe pump and glass capillary tube (Internal Diameter of 0.45 mm). I connect a 1/4” air line hose from the syringe to the capillary The bubble is formed at the tip...
Thread 'Calculate minimum RPM to self-balance a CMG on two legs'
Here is a photo of a rough drawing of my apparatus that I have built many times and works. I would like to have a formula to give me the RPM necessary for the gyroscope to balance itself on the two legs (screws). I asked Claude to give me a formula and it gave me the following: Let me calculate the required RPM foreffective stabilization. I'll use the principles of gyroscopicprecession and the moment of inertia. First, let's calculate the keyparameters: 1. Moment of inertia of...
Back
Top