A sleigh with a mass of 150 kg from rest is horizontally towed to the left
. This is done using a rope that makes an angle of 30 ° with the horizontale. The tensile force is 200 N. (Neglect friction forces.)
a. What is the horizontal component of the force?
b. What acceleration will the sleigh get ?
F: m xa[/B]
The Attempt at a Solution
for a ) horizontal component zo
Fx = 200 N x cos (30°) = 173.2N
a= F/m => 173.2N / 150 kg = 1.155m/s^2
For b ) i thought we had to use tensile force ?? why do we use Fx instead of tensile force ???[/B]