Dynamics of axially loaded bar

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The discussion centers on the derivation of the consistent mass matrix for an axially loaded bar as presented in David Hutton's "Fundamentals of Finite Element Analysis." The key point raised is the assumption of different forces acting on the ends of a differential element, which is justified by the presence of initial axial loading conditions. This loading can be exemplified by an impact, such as striking the bar with a hammer, which generates a non-zero net force on the differential elements. The propagation speed of stress waves in the bar is determined by the one-dimensional wave equation, specifically expressed as √(E/ρ).

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svishal03
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Hi,

I have a simple question and shall be grateful if helped.

See the attached word document.I have been reading the derivation of the consistent mass matrix- for the axially loaded bar.My question is:

1)While formng the equation 10.51 (referring figure 10.7), the author considers the equilibrium of the differential element of length dx.

But the forces on each end ofthe differential element can be different only if there is some load between the two ends.

IS this some kind of error that the author David Hutton of the concerned text on Fundamentals of Finite Element analysis has not considered the force(s) between the ends?

Please help.

Vishal
 

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The author is assuming some axial loading initial condition. It is this loading that causes the non-zero net force on the differential elements. A common example would be striking the end of the bar with a hammer. The speed with which the stress wave propagates down the rod is determined using the one dimensional wave equation (10.52) and equals [itex]\sqrt{E/ρ}[/itex].
 
The bar can move. The equation is just Newton's second law applied to the small element. Force = mass times acceleration.
 

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