Dynamics Question: Finding Fa using mass and acceleration

Click For Summary
The discussion revolves around calculating the applied force (Fa) on a 15kg object thrown into the air with an initial acceleration of 8.8 m/s². The user initially struggled with the correct equation, mistakenly using Fa = ma - Fg instead of the correct Fa = ma + Fg. After receiving clarification, they realized that the gravitational force (Fg) should be treated as negative because it acts in the opposite direction to the applied force. The correct calculation led to an applied force of 279 N. The user expressed gratitude for the assistance in identifying their mistake.
Apollinaria
Messages
82
Reaction score
0
Hello again forum :smile: I am still studying for that unit test and am still having problems with dynamics... I've attached the problem with the calculations/solutions. Basically, I don't understand why I'm getting the wrong answer. Probably b/c idk what the heck I'm doing :eek:

Homework Statement



15kg object thrown into the air. Initial acceleration is 8.8m/s^2. Find applied force.


Homework Equations



Please see attachment.

The Attempt at a Solution



Please see attachment. Btw, I realize Fa needs to be positive.

Please advise regarding correct way of solving?.. Thank you for your time once again:smile:

EDIT: I found my mistake. However, I still don't understand why "that" is the correct solution.
My Fg value had to be negative;
Fa= (15kg x 8.8m/s^2) - (-147.15)
Fa= 279.15
 

Attachments

  • Dynamics.jpg
    Dynamics.jpg
    24.4 KB · Views: 485
Physics news on Phys.org
The force available to accelerate the object (Fnet) is equal to the sum of all the forces acting on the object.

Fnet = FA + (-Fg)
or
Fnet = FA - Fg

Fg is negative because it's in the oposite direction to FA.

Rearrange..

FA = Fnet + Fg

= ma + mg
= m (a+g)
= 15 (8.8 + 9.81)
= 279 N
 
You have done everything right, you simply made a mistake while solving the equations.
You wrote:
FA-Fg=ma
FA=ma-Fg. <--- This is wrong. It should be FA=ma+Fg. :wink:
 
Well spotted. I looked at his working and didn't see that error.
 
CWatters said:
The force available to accelerate the object (Fnet) is equal to the sum of all the forces acting on the object.

Fnet = FA + (-Fg)
or
Fnet = FA - Fg

Fg is negative because it's in the oposite direction to FA.

Rearrange..

FA = Fnet + Fg

= ma + mg
= m (a+g)
= 15 (8.8 + 9.81)
= 279 N

Thank you Watters :biggrin: That organizes it a little better lol. In regard to your last post, I am very much female by the way :wink:
 
Pranav-Arora said:
You have done everything right, you simply made a mistake while solving the equations.
You wrote:
FA-Fg=ma
FA=ma-Fg. <--- This is wrong. It should be FA=ma+Fg. :wink:

Eek! So sad that I didn't notice that... I'm sorry you had to point it out but thank you once again :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
3
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 12 ·
Replies
12
Views
910
  • · Replies 17 ·
Replies
17
Views
3K
Replies
2
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K