How to find Coefficient of Friction w/ Fa and mass?

In summary, the team of six poodles are pulling a 14.0 kg sled at 8.0 m/s with a 66N force and the coefficient of kinetic friction is 0.48.
  • #1
HomiesontheRise
4
0

Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
 
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  • #2
HomiesontheRise said:

Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
HomiesontheRise said:

Homework Statement


A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s

IF the dogs are applying a 66N force, find the coefficient of kinetic friction

Homework Equations


Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+Fa

The Attempt at a Solution


I honestly have no clue where to start for this question.
Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.
 
  • #3
So I started by finding the Net Force which was 0 due to the fact that there is no acceleration (velocity is constant).
Then found Force of Friction using Fnet and Fa with the formula Fnet=Fa+(-Ff).
Then found Fn using Fn=mg.
Finally, I user Ff=Fn*u to find u

MY WORK
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
 
  • #4
Please tell me if you see any errors in my calculations
 
  • #5
PhanthomJay said:
Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.
Does this look right?
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
 
  • #6
Look
HomiesontheRise said:
Does this look right?
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u
Looks good!
 

1. What is the definition of coefficient of friction?

The coefficient of friction is a measure of the resistance between two surfaces in contact that prevents them from sliding against each other. It is represented by the symbol μ (mu) and is a dimensionless quantity.

2. How is the coefficient of friction calculated?

The coefficient of friction is calculated by dividing the force of friction (F) by the applied normal force (N). This can be represented by the equation μ = F/N.

3. What is the role of Fa and mass in determining the coefficient of friction?

Fa (applied force) and mass are both factors that affect the coefficient of friction. The magnitude of the applied force and the mass of the objects in contact can influence the frictional forces between them, thus affecting the coefficient of friction.

4. How can the coefficient of friction be measured?

The coefficient of friction can be measured using various methods, such as the inclined plane method, the block on block method, or the sliding block method. In these experiments, the force of friction is measured and used to calculate the coefficient of friction.

5. What are some real-world applications of the coefficient of friction?

The coefficient of friction is an important factor in many everyday situations, such as walking or driving on different surfaces, the design of tires and brakes for vehicles, and the performance of sports equipment. It is also used in engineering and construction to ensure the stability and safety of structures and machinery.

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