The problem involves a scenario where a team of six poodles is pulling a sled, and the objective is to find the coefficient of kinetic friction given the mass of the sled and the force applied by the dogs. The context is rooted in dynamics and frictional forces.
Some participants have provided calculations and reasoning regarding the net force and frictional force, while others have offered guidance on ensuring the problem is read carefully. There is an ongoing verification of the calculations presented.
Participants are working under the assumption that the sled is moving at a constant velocity, which implies that the net force is zero. There is a focus on the equations of motion and friction without resolving the final value of the coefficient of friction.
HomiesontheRise said:Homework Statement
A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s
IF the dogs are applying a 66N force, find the coefficient of kinetic friction
Homework Equations
Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+FaThe Attempt at a Solution
I honestly have no clue where to start for this question.
Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.HomiesontheRise said:Homework Statement
A team of six poodles are pulling a 14.0 kg sled at 8.0 m/s
IF the dogs are applying a 66N force, find the coefficient of kinetic friction
Homework Equations
Ff=u*Fn
Fnet=ma
Fnet=(-Ff)+FaThe Attempt at a Solution
I honestly have no clue where to start for this question.
Does this look right?PhanthomJay said:Well you have correctly listed the relevant equations, now first identify what the acceleration is and solve. Read the problem carefully.
Looks good!HomiesontheRise said:Does this look right?
1.
Fnet=0 Fnet-Fa=-Ff 0-66=-Ff -66=-Ff
2.
Fn=mg Fn=14kg*9.8 Fn=137.2
3.
Ff=u*Fn u=Ff/Fn 66/137.2=u 0.48=u