Dynamics Question - Simple but stuck

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Homework Help Overview

The discussion revolves around a dynamics problem involving forces, friction, and equilibrium. The original poster presents equations related to force and friction, attempting to solve for unknowns in a system described by a diagram.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between forces, coefficients of friction, and normal force. There are attempts to manipulate equations to eliminate unknowns, and questions arise regarding the correctness of units and the implications of steady motion on acceleration.

Discussion Status

Participants are actively engaging with the problem, offering guidance on how to eliminate one of the unknowns to simplify the equations. There is recognition of a potential error in unit conversion, and the discussion reflects a collaborative effort to clarify the setup and approach to the problem.

Contextual Notes

There is mention of a listed answer, which adds a layer of complexity to the participants' attempts to reconcile their calculations with expected results. The original poster expresses uncertainty about the implications of steady motion on the forces involved.

Chantry09
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Homework Statement



http://img511.imageshack.us/img511/3732/dynamics01fm7.jpg

Homework Equations



F = M x A
F = u (coefficient of friction) x N

The Attempt at a Solution



http://img508.imageshack.us/img508/7526/dynamics02ry1.jpg

W sin 30 = 50000
W cos 30 = 86602.54

1Mg = 10,000KG

86,602.54 = N + P sin 20
50,000 + F = P cos 20

Im left with two unknowns, P and F, and i don't know what i need to do to get either one of them.
 
Last edited by a moderator:
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Looks to me like you have two equations and three unknowns. Get rid of F by using what you know about friction (one of your equations listed). Then you'd have two equations and two unknowns--which works out just right.
 
Are you saying i should combine the two equations into one? Like this?

u x N = M x A

Since its steadily moving up a = 0 so:

0.15 x N = 0

Surely that can't be right? If its any help, answer is listed as 6230 N, but i can't get it myself. It isn't accelerating, so a = 0, but when i put that into the equation it says F and therefore N = 0 which i know can't be right.
 
Last edited:
You lost me on that last post! All I'm saying is to use [itex]F = \mu N[/itex] to eliminate F from your two equations. Then you can solve them together.

Also: Shouldn't 1Mg = 1,000KG (not 10,000)? (Mg is a rather odd unit!)
 
Yeah your right, I am sorry, its 1000KG. I am not quite sure how to use F = [tex]\mu[/tex] N

I don't know F, and i don't know N, I only know that [tex]\mu[/tex] is 0.15, and i don't know how i can work out F or N.
 
Last edited:
Once you eliminate F from your equations (from post #1, after you correct them) by replacing it with [itex]\mu N[/itex], you will have two equations and two unknowns (N and P). Solve those two simultaneous equations and you'll find P.

(To solve them, if that's the problem, take one of them and rewrite it to solve for N in terms of P. Then use it to replace N in the other equation. Then you'll have one equation with only P as your unknown.)
 

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