E-B crossed fields parallel plate

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Homework Help Overview

The problem involves a parallel plate setup with a potential difference and a magnetic field, where an electron is released from rest at one plate. The goal is to analyze the conditions under which the electron will reach the opposite plate based on the given parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the electron's motion and the forces acting on it, including electric and magnetic forces. There are attempts to derive equations of motion for the electron, with some questioning the assumptions made about the radius of curvature and the choice of coordinate directions.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the motion of the electron and the forces involved. Some guidance has been offered regarding the need to consider both x and y components of acceleration, but no consensus has been reached on the correct approach or equations to use.

Contextual Notes

Participants are working under the constraints of the problem statement, including the potential difference and magnetic field strength, while questioning the validity of their assumptions and the setup of their equations.

unscientific
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Homework Statement



A parallel plate has p.d. V with one end 0V and the other +V. B-field of strength B has direction along plates. An electron is released from rest at 0V plate. Show that if V is less than e(DB)2/(2m) the electron will not reach the other plate.

Homework Equations





The Attempt at a Solution



At half-way inbetween the plates, the radius must be d/2

R = mv/Bq

d/2 = m*√(2*e*0.5V/m) / (Bq)

I end up with e(DB)2/(4m) instead..
 
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unscientific said:
At half-way inbetween the plates, the radius must be d/2

Hello.
I don't follow your statement. Could you just as well reason that when the electron is 3/4 of the way across, then the radius must be d/4? If so, would you get the same answer?

I think you're going to need to set up the equations of motion for the x and y components of acceleration.
 
TSny said:
Hello.
I don't follow your statement. Could you just as well reason that when the electron is 3/4 of the way across, then the radius must be d/4? If so, would you get the same answer?

I think you're going to need to set up the equations of motion for the x and y components of acceleration.

define x as upwards, y into the plate.

max = eV/d

may = qvB

x2 + y2 = d2

is that right?
 
Let me make sure I understand your choice of directions and signs. Correct me if I'm wrong. You're choosing the electric field in the negative x direction so that the E field accelerates the electron in the positive x direction. The x-axis is oriented perpendicular to the plates.

y-axis is parallel to the plates and B is parallel to the plates but perpendicular to both the x-axis and the y-axis such that when the electron starts moving the B field begins to deflect the electron toward positive y.

But once the electron is deflected some in the y-direction by the B field, the electron will then have a y-component of velocity. So, the magnetic field will then cause some force parallel to the x-axis! So, you need to include a magnetic force term in your equation for ax.

The electron is going to move along a curved path, so you can't say x2+y2 = d2 (if d represents the separation of the plates).
 
Last edited:

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