E = F/q - (V*B)Lorentz Force Law Part 1: Finding E

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SUMMARY

The discussion centers on the application of the Lorentz force law to derive the electric field E in terms of the velocity v and magnetic field B for a charged particle moving at constant velocity. The formula used is F = q(E + v × B), leading to the conclusion that E = -v × B when the particle experiences no acceleration. Participants confirm the correctness of this derivation, emphasizing the importance of justification in academic discussions.

PREREQUISITES
  • Understanding of the Lorentz force law
  • Familiarity with vector cross products
  • Knowledge of electric and magnetic fields
  • Basic principles of classical mechanics
NEXT STEPS
  • Study the implications of constant velocity on force in classical mechanics
  • Explore the relationship between electric fields and magnetic fields in electromagnetic theory
  • Learn about the applications of the Lorentz force in particle physics
  • Investigate the mathematical derivation of the Lorentz force law
USEFUL FOR

Students of physics, particularly those studying electromagnetism, educators teaching classical mechanics, and anyone interested in the dynamics of charged particles in electric and magnetic fields.

imy786
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Homework Statement



The motion of a charged particle P, observed in an inertial frame S. It is found that P moves with constant velocity v through a region of space where there is a uniform electric field E and a uniform magnetic field B. The speed v = |v|and the field magnitudes E = |E| and B = |B| are all non-vanishing.

Use the Lorentz force law to express E in terms of v and B.

Homework Equations



Lorentz force formula-

F=q(E+v*B)

The Attempt at a Solution



F=q(E+v*B)

F/q = E+ v*B

F/q - (V*B) = E
 
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The charged particle is moving at constant velocity. What does that tell you about the force?
 
constant velocity= no accelration , therefore no force

F/q - (V*B) = E

E= -v * B
 
You got it!
 
anyone else can confirm if my answer is correct
 
looks okay.
 
You don't trust me, imy786?
 
Its correct.
 
its that i don't trust u...anyone can say its correct...without any justification...

and as you havnt got a homework helper badge...its harder to belie...

it doesn't mean i don't believe u..

thanks for your help
 
  • #10
He justified it. If it makes sense to you, then that should be enough to at least turn it in.
 
  • #11
No worries.

Thanks for the backup, StatMechGuy...
 
Last edited:

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