# E Field caused by infinite plate

What is the equation for the electric field caused by an infinite plate of charge? Is it sigma/2epsilon0?

So does that mean that the distance from a point to the plate doesn't matter in computing the E field? How does this change if a solid conducting slab with significant thickness (2 cm) is used? I know that the charges should build up on each side, with half of the charges on each side, so is that treated then as 2 plate charges?

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Tom Mattson
Staff Emeritus
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WarpDrive said:
So does that mean that the distance from a point to the plate doesn't matter in computing the E field?
That's right. An infinite plate of charge has a constant, uniform E field.

How does this change if a solid conducting slab with significant thickness (2 cm) is used? I know that the charges should build up on each side, with half of the charges on each side, so is that treated then as 2 plate charges?
See the following website:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elesht.html

The first segment, entitled Electric Field: Sheet of Charge covers the thin plate, and the second segment, entitled Electric Field: Parallel Plates covers thick plates.