E-field of a constant velocity charged particle

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    Charged Electric Field
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SUMMARY

The discussion centers on the visualization of the electric field generated by a constant velocity charged particle, specifically using the Liénard–Wiechert potential. Participants critique the clarity and accuracy of the plotted electric field lines, emphasizing the need for proper labeling and mathematical representation. Key points include the distinction between electric field lines and the representation of information about the particle's position, as well as the necessity of accounting for magnetic fields in moving charge scenarios. The conversation highlights the importance of accurate graphical representation in electromagnetic theory.

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  • Familiarity with electric and magnetic fields in classical electrodynamics
  • Knowledge of Lorentz transformations
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  • #31
Ibix said:
The field around a straight current carrying conductor is a magnetic field with no electric field.
I've a doubt here. In the model of straight conductor carrying current (a flow of electrons moving with constant velocity) is the net charge inside each volume/segment of the conductor supposed to be zero (due to the presence of positive metal ions) ?
 
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  • #32
cianfa72 said:
I've a doubt here. In the model of straight conductor carrying current (a flow of electrons moving with constant velocity) is the net charge inside each volume/segment of the conductor supposed to be zero (due to the presence of positive metal ions) ?
you are right, even the hydrogen atom is a dipole, i.e. has a electric field
 
  • #33
aliinuur said:
you are right, even the hydrogen atom is a dipole, i.e. has a electric field
Since the 1s ground state of the hydrogen atom is spherically-symmetric, can you tell us in which direction this electric field points?
 
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  • #34
renormalize said:
Since the 1s ground state of the hydrogen atom is spherically-symmetric, can you tell us in which direction this electric field points?
its dipole moment has equal chance of pointing in any direction :)
 
  • #36
The thread will remain closed. Thanks for all who tried to help
 

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