E=mc2 Problem Help: Comparing Reactors and Batteries

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The discussion centers on the application of Einstein's equation E=mc² in the context of nuclear reactors and batteries. It establishes that while E=mc² accurately describes mass loss in nuclear reactions, it does not apply to chemical reactions in batteries due to the significantly lower energy scales involved. The energy from nuclear reactions is typically in the MeV range, whereas chemical reactions operate in the eV range, making the mass loss negligible in batteries. The conclusion emphasizes that E=mc² is relevant for nuclear energy but not for chemical energy transformations.

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the celebrated equation E=mc2 or m=E/c2 (c is the speed of light) tells us how much mass is loss, m, must be suffered by a nuclear reactor in order to generate a given amount of energy, E/ Which of the following statements is correct?

a)The same equation, E=mc2 or m=E/c2, also tells us how much mass loss, m, must be suffered by a flashlight battery when the flashlight puts out a given amount of energy, E.

b) The equation E=mc2 applies to nuclear energy in a reactor, but not to chemical energy in a battery.
 
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Why would either be true? or Why would E=mc2 be true for a nuclear reaction, but not true for a chemical reaction. Nuclear reactions usually involved energies in the MeV range, while chemical reaction energies are in the eV range.
 
Einstein developed E=mc^2 without knowing anything about the nucleus. His paper published in 1905 predated Rutherford's discovery of the nucleus by about six years. In his http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf" , Einstein showed that any object emitting/absorbing light of energy L will lose/gain mass in the amount m = L/c^2. I think that should tell you the answer to the question.

AM
 
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