Earnshaw's Theorem and electrostatics

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SUMMARY

Earnshaw's Theorem establishes that stable equilibrium in electrostatics is impossible. The theorem is proven by analyzing a charge Q at point P and applying Gauss's Law, which leads to a contradiction when assuming stable equilibrium. The discussion also explores a scenario with point charges at the corners of a square, examining the stability of a test charge q placed at the center. The divergence of the electric field E being zero does not imply stable equilibrium, as it can indicate metastable states.

PREREQUISITES
  • Understanding of Earnshaw's Theorem
  • Familiarity with Gauss's Law
  • Knowledge of electric fields and charge interactions
  • Concept of stable versus metastable equilibrium
NEXT STEPS
  • Study the implications of Earnshaw's Theorem in electrostatics
  • Learn about Gauss's Law applications in different geometries
  • Investigate the concept of metastable states in physics
  • Explore electric field calculations for multiple point charges
USEFUL FOR

Students of physics, particularly those studying electrostatics, educators teaching concepts of electric fields, and researchers exploring stability in charged systems.

arishorts
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Homework Statement


14: a: It is impossible to have a stable equilibrium in electrostatics. This idea is known as Earnshaw’s Theorem. Let’s prove this fact. Assume that at a particular point P that a charge Q is in a stable equilibrium. Think about the direction of E⃗ necessary for the equilibrium. Now use Gauss’ Law with a spherical gaussian surface centered on P. Show that this leads to a contradiction.
b: Imagine a square in the xy plane with a point charge Q fixed at each corner. Now put a test charge q in the exact center of the square. What direction(s) can we move q in for which the equilibrium is stable? For which it is not stable? Explain.


Homework Equations


Gauss's equation: (E*A)/(Qenclosed*(Permittivity of free space))


The Attempt at a Solution


I've figured out that the direction of E has to be inward, but i don't understand why. With some research I've found the proof where the divergence comes out to zero, but wouldn't that mean it achieves stable equilibrium? Seems a bit contradictory. Also, if you use a spherical versus a circular surface, you get a difference in answer by a factor of 1/3... That's the best i can do. Please help.
 
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arishorts said:
the divergence comes out to zero, but wouldn't that mean it achieves stable equilibrium?
No, that could be metastable, like a ball on a surface that is fully horizontal.
 
I like your analogy, a lot actually. But how can i prove that using Gauss' theorem leads to a contradiction?
 

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