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Easy-acceleration with unit vectors

  1. Sep 9, 2012 #1

    PEZenfuego

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    1. The problem statement, all variables and given/known data

    untitled.jpg

    r1=(0m)
    r2=(2000i + 1000j)m
    v1=(200j)m/s
    v2=(200i-100j)m/s
    2. Relevant equations
    tantheta=vy/vx

    v2^2=v1^2+2ax
    v2=v1+at
    x2=x1+v1t+1/2at^2

    3. The attempt at a solution

    IMG_20120909_150513.jpg

    Thank you for any help
     
    PEZenfuego, Sep 9, 2012
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  3. Sep 9, 2012 #2

    Draco27

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    So what do we have to find??
     
    Draco27, Sep 9, 2012
  4. Sep 9, 2012 #3

    PEZenfuego

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    find the saucer's acceleration in unit vectors and in terms of magnitude and direction.
     
    PEZenfuego, Sep 9, 2012
  5. Sep 9, 2012 #4

    SammyS

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    Are those kinematic equations for components of vectors, or for vectors themselves?
     
    SammyS, Sep 9, 2012
  6. Sep 9, 2012 #5

    PEZenfuego

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    If you click the first picture, you will have an understanding equal to mine. I'm sorry.
     
    PEZenfuego, Sep 9, 2012
  7. Sep 10, 2012 #6

    SammyS

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    Sorry for the slow response.

    I should have been more direct with my earlier response.

    The set of kinematic equations you have
    (v2)2=(v1)2+2ax
    (v2)=(v1)+at
    x2=x1+(v1)t+1/2at2​
    are valid for each component of displacement, velocity, and acceleration.

    So you have two such sets of kinematic equations:
    (v2)x2 = (v1)x2 + 2axx
    (v2)x = (v1)x + axt
    x2 = x1 + (v1)xt + 1/2axt2

    (v2)y2 = (v1)y2 + 2ayy
    (v2)y = (v1)y + ayt
    y2 = y1 + (v1)yt + 1/2ayt2
    ​
     
    SammyS, Sep 10, 2012
  8. Sep 10, 2012 #7

    PEZenfuego

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    It makes sense now. thank you.
     
    PEZenfuego, Sep 10, 2012
  9. Sep 10, 2012 #8

    SammyS

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    What did you get for answers?
     
    SammyS, Sep 10, 2012
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