Easy percentage prob (for pro) hahah

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SUMMARY

The discussion focuses on calculating the natural percent abundance of the heavier isotope of lithium, which has an average atomic weight of 6.941. The two stable isotopes have mass numbers of 6.015 and 7.016. Participants suggest using a variable, denoted as "x," to represent the proportion of the heavier isotope, allowing for the formulation of an equation to solve the problem. This method provides a clear approach to determining the isotopic abundance based on the average atomic weight.

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  • Knowledge of natural abundance concepts
  • Familiarity with lithium isotopes and their mass numbers
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Homework Statement



Lithium has an average atomic weight of 6.941. If the only two stable
isotopes have mass numbers of 6.015 and 7.016, what is the natural
percent abundance of the heavier isotope?




Homework Equations



any help would be good. thanks ( ican do it easy when they give percent but this is different

The Attempt at a Solution

 
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geffman1 said:
Lithium has an average atomic weight of 6.941. If the only two stable
isotopes have mass numbers of 6.015 and 7.016, what is the natural
percent abundance of the heavier isotope?

Hi geffman1! :smile:

General technique … give the answer a letter, and use that letter to get an equation.

in this case, call the proportion of the heavier isotope "x" (so the proportion of the lighter isotope is 1 - x), and write an equation. :wink:
 

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