Effect of Adding Water on Reaction Rate: Rate Law Theory Question

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The addition of 500mL of water to the reaction A(aq) + D(l) -> B(aq) + C(aq) results in a decrease in the reaction rate. This is due to the dilution of the reactants, specifically the concentration of A and H+, as indicated by the rate law k[H+][A]. The dilution leads to fewer effective collisions between reactant molecules, thereby lowering the overall reaction rate.

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Homework Statement


Consider: A(aq) + D(l) -> B(aq) + C(aq)
Rate Law: k[H+][A]

Does the rate increase, decrease, or stay the same, when 500mL of water are added to the solution?

Homework Equations


The Attempt at a Solution


My thought was no. The water doesn't have any effect on the chemical reaction. All I could think of was a dipole dipole interaction between the H2O(l) and the H+ which might lower the collision factor because of interference, which in turn would lower the rate of the reaction.

Again though, I'm not sure. Can someone shed some light please? My exam is on Monday and this question is coming home drunk and beating me up.Edit: Nevermind. The addition of more solvent dilutes the solution. Decrease in concentration = decrease in rate.
 
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Greg Bernhardt said:
I'm sorry you are not finding help at the moment. Is there any additional information you can share with us?
Hi Greg,

In the last line, he indicated that he got it solved.

Chet
 
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