Effective Weight of Falling Object

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SUMMARY

The effective weight of a falling branch can be determined by calculating its kinetic energy and velocity upon impact. The formula for kinetic energy is E = (9.8 m/s²) * m * h, where m is the mass in kilograms and h is the height in meters. The velocity of the branch just before impact can be calculated using v = √(2gh), resulting in a theoretical velocity of approximately 4.43√h. The force of impact can be estimated using F = m * a, where acceleration can be derived from the change in velocity over the duration of the collision.

PREREQUISITES
  • Understanding of basic physics concepts such as mass, force, and acceleration
  • Familiarity with the equations of motion, specifically kinetic energy and velocity calculations
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to perform calculations involving square roots and basic algebra
NEXT STEPS
  • Research the effects of air resistance on falling objects
  • Learn about the principles of momentum and impulse in physics
  • Explore real-world applications of kinetic energy in safety assessments
  • Investigate the physics of impact forces and their implications in engineering
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Physics students, engineers, safety inspectors, and anyone involved in assessing the risks associated with falling objects, particularly in urban environments.

damon
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I'm am trying to determine the effective weight of a branch that falls from a tree to the ground. When I say the "effective weight" I mean the effect of the increased speed of the branch as it falls.

The branch would fall from say 30 metres (say 90 feet) and would initially weigh 1 kilgrams (say 2.2 pounds).

I'd appreciate either the answer or a formula to work it out. BTW, I'm not a student we are just fighting our local Council (in Sydney) to remove a tree! They think the branches are small but when they hit they hurt!

Thanks in advance for any assistance.

Damon
 
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The mass of an object never changes.

You might look into the kinetic energy of the branch. The faster it moves, the more energy it has, and the farther it falls, the faster it moves. It's easy to show that the energy of an object falling from height h and mass m has energy

E = (9.8\frac{\textrm{m}}{\textrm{s}^2})mh

Edit: Just took out some superfluous information that might be a source of confusion.

cookiemonster
 
Last edited:
(9.8\frac{\textrm{m}}{\textrm{s}^2})mh = 1/2 mv^2
Calculate v - velocity.


Hack, when I started, I’m going to finish it :) :
v ={\sqrt{2gh}}
v= 4.43{\sqrt{h}}
When you have h (height of that branch/three) you can calculate its velocity (you can see how it doesn’t depends on mass). But this is theoretical value calculated without air resistance (+ if the branch if alive with leafs, this “friction” factor is greater).

How much it weights? Weight is measure for force so you can calculate it (again theoretically) from:
F = m*a you don’t know a, but let’s say that collision lasts t=0.3s, and branch decelerates form v to v=0, than you can say: a = v / t^2. (you can use “ordinary” weight of branch as m).

Hope I helped,
Greetz

P.S. I have to mention that this is somehow interesting/funny to me, your fighting to cut tree, that as you say, endangers you, and we have an unexploded Tomahawk in our backyard, that we are too trying to get rid off :smile:. What a world :smile: (NHF – just comparing).
 

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