Efficiency of a hydroelectric power station

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SUMMARY

The discussion centers on calculating the efficiency of a hydroelectric power station, specifically focusing on the conversion of potential energy from water into electrical energy. The efficiency of the dam is confirmed to be 90%. The participant initially struggled with calculating the input energy based on water's kinetic energy and volume per minute but ultimately clarified that the relevant calculation involves potential energy. The final conclusion emphasizes the importance of simplifying calculations in this context.

PREREQUISITES
  • Understanding of potential energy and kinetic energy concepts
  • Familiarity with hydroelectric power generation principles
  • Basic knowledge of efficiency calculations in energy systems
  • Ability to perform unit conversions, specifically volume per second to volume per minute
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  • Research the formula for calculating potential energy in hydroelectric systems
  • Learn about the efficiency metrics used in hydroelectric power stations
  • Explore the impact of water flow rates on energy production
  • Investigate common pitfalls in energy calculations for renewable resources
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Engineers, energy analysts, and students in renewable energy fields who are interested in understanding the efficiency and calculations involved in hydroelectric power generation.

greg_rack
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Homework Statement
A hydroelectric power station uses the water in a reservoir to power the generators. The water
falls through a vertical height of 150m to the turbines which power the generators.
The efficiency of the power station is 90% and the output power of the power station is
1800 MW.
The gravitational field strength is 10Nkg–1 and the density of water is 1000 kgm–3.
What volume of water passes through the turbines in one minute?
A. 6.48 ×10^4 m3
B. 7.20 ×10^4 m3
C. 8.00 ×10^4 m3
D. 6.48 ×10^7 m3
E. 7.20 ×10^7 m3
F. 8.00 ×10^7 m3
Relevant Equations
efficiency=useful output/tot input
Power=E/t
Kinetic energy=0.5mv^2
Density=m/v
I have found the input power through the efficiency formula, and I deducted that the input energy must derive only from water's kinetic energy... from which have mass/s and then finally the volume/s.
After all the calculations and having multiplied the volume/s by 60, I get the result of 6.48 x 10^10 m3 which isn't listed... what am I getting wrong?
 
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Just to be annoying they ask you for volume per minute !
 
hutchphd said:
Just to be annoying they ask you for volume per minute !
Yes sure, I forgot to mention... the result I wrote comes from multiplying my Volume per second by 60!
 
The dam converts the Potential Energy of a volume of water to electrical energy with an efficiency of 90%. What you say is correct but overcomplicated...one never need to worry about the speed explicitly.
So how much energy does one ##m^3## of water produce?
 
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hutchphd said:
The dam converts the Potential Energy of a volume of water to electrical energy with an efficiency of 90%. What you say is correct but overcomplicated...one never need to worry about the speed explicitly.
So how much energy does one ##m^3## of water produce?
I have barely did it... I had made everything unnecessarily complex! :cry:
 
greg_rack said:
I have barely did it... I had made everything unnecessarily complex! :cry:
Did you find your answer?
 
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Lnewqban said:
Did you find your answer?
Yes I did, with potential energy
 
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