Calculate Efficiency of Motor Lifting 0.050kg Block at 0.40m/s

  • #31
malemdk said:
Rate of change of potential energy d(mgh)/dt =mg dh/dt = mg x v = Fx v = power needed to maintain the constant velocity, where from you can find efficiency if you know the input power
The fact that you used d(mgh)/dt confuses me, since we don't do that, and you put it on one line.
 
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  • #32
sorry
 
  • #33
TomHart said:
Just one minor issue. The voltage was 3.0 V.
yes
 
  • #34
IDK10 said:
The fact that you used d(mgh)/dt confuses me, since we don't do that, and you put it on one line.
Are you familiar with the equation Power = Force x Velocity?
 
  • #35
Yes , I designed many ,many machines using this equation .
it can be derived from Newtons second law
 
  • #36
malemdk said:
Yes , I designed many ,many machines using this equation .
I was asking @IDK10. He seemed to be having trouble understanding your solution.
 
  • #37
ok
 

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