Efficiency of a hydroelectric power station

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Homework Help Overview

The discussion revolves around the efficiency of a hydroelectric power station, focusing on the conversion of water's potential energy into electrical energy. Participants are examining the calculations related to input power and energy derived from water's kinetic energy and potential energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculations for input energy and the conversion of potential energy, questioning the accuracy of their results and the relevance of speed in the calculations. There is also a mention of the specific requirement for volume per minute, leading to some confusion.

Discussion Status

The discussion is ongoing with participants sharing their calculations and questioning their complexity. Some have found answers related to potential energy, while others are still exploring their reasoning and calculations.

Contextual Notes

Participants are working under the constraint of needing to express volume in terms of per minute, which has led to some confusion in their calculations. There is also a mention of an efficiency rate of 90% for the energy conversion process.

greg_rack
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Homework Statement
A hydroelectric power station uses the water in a reservoir to power the generators. The water
falls through a vertical height of 150m to the turbines which power the generators.
The efficiency of the power station is 90% and the output power of the power station is
1800 MW.
The gravitational field strength is 10Nkg–1 and the density of water is 1000 kgm–3.
What volume of water passes through the turbines in one minute?
A. 6.48 ×10^4 m3
B. 7.20 ×10^4 m3
C. 8.00 ×10^4 m3
D. 6.48 ×10^7 m3
E. 7.20 ×10^7 m3
F. 8.00 ×10^7 m3
Relevant Equations
efficiency=useful output/tot input
Power=E/t
Kinetic energy=0.5mv^2
Density=m/v
I have found the input power through the efficiency formula, and I deducted that the input energy must derive only from water's kinetic energy... from which have mass/s and then finally the volume/s.
After all the calculations and having multiplied the volume/s by 60, I get the result of 6.48 x 10^10 m3 which isn't listed... what am I getting wrong?
 
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Just to be annoying they ask you for volume per minute !
 
hutchphd said:
Just to be annoying they ask you for volume per minute !
Yes sure, I forgot to mention... the result I wrote comes from multiplying my Volume per second by 60!
 
The dam converts the Potential Energy of a volume of water to electrical energy with an efficiency of 90%. What you say is correct but overcomplicated...one never need to worry about the speed explicitly.
So how much energy does one ##m^3## of water produce?
 
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hutchphd said:
The dam converts the Potential Energy of a volume of water to electrical energy with an efficiency of 90%. What you say is correct but overcomplicated...one never need to worry about the speed explicitly.
So how much energy does one ##m^3## of water produce?
I have barely did it... I had made everything unnecessarily complex! :cry:
 
greg_rack said:
I have barely did it... I had made everything unnecessarily complex! :cry:
Did you find your answer?
 
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Lnewqban said:
Did you find your answer?
Yes I did, with potential energy
 
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