Efficiency of Carnot Engine w/ 0.75kg Ideal Gas

[Da-Force]

LOL! Well, I thought that too... But then it would have to have been curved... I know you CAN calculate at any point the T because that is definitely a given on any Pressure versus Volume graph... So tell me, did I explain that part correctly now that we've cleared up the confusion?

 

[Cyrus]

I got it! BOOOO

 

[Cyrus]

I thought your graph said 1-2 was a constant temperature line!

<Pulls my hair out>

None of it is constant temperature. You have to find the gas constant using:

$$PV=mRT$$

Then do as you guys tried by going around the entire process.

You will find that $$T_H = 835.714$$

and $$T_L = 390$$

use that in carnot and you will get:

$$\eta_{th,rev} = 1- \frac{T_L}{T_H} = 1 - .4666 = .5333$$

That was an AWFUL problem in my opinion.

 

[Da-Force]

I got it! BOOOO

Oh darn it :-(

Now this is the part where you explain how you did it with your ever-knowing knowledge and mind.

 

[Da-Force]

Oh wait.. Now I forget something... T(h) would be the hottest temperature and T(c) would be the coldest?

I kept thinking initial and final Explain it to me again

 

[Cyrus]

No, I just stole what you did. (with some refining)

 

[endeavor]

Wow, thanks a lot!
I kept taking the inital temperature as the hot too!

 

[Cyrus]

Tell your teacher that problem is unclear.