Eigenvalues of operator in dirac not* (measurement outcomes)

Click For Summary

Homework Help Overview

The discussion revolves around the measurement outcomes of a quantum operator represented as |0⟩⟨1| + |1⟩⟨0|, with |0⟩ and |1⟩ being orthonormal states. Participants are exploring the eigenvalues associated with this operator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve the eigenvalue equation A|Ψ> = a|Ψ> by assuming a specific form for |Ψ>. They derive relationships between the coefficients α and β and propose eigenvalues of -1 and 1. Some participants question the assumption made about the state |Ψ> and reference the completeness relation.

Discussion Status

The discussion includes attempts to clarify the assumptions made in the original poster's approach. Some participants provide feedback on the validity of the calculations, while others suggest looking up additional concepts like the completeness relation to enhance understanding. There is no explicit consensus on the correctness of the eigenvalues yet.

Contextual Notes

Participants express uncertainty about the foundational concepts involved in the problem, indicating a need for further exploration of the completeness relation and its implications for the state |Ψ>.

12x4
Messages
28
Reaction score
0

Homework Statement


A measurement is described by the operator:

|0⟩⟨1| + |1⟩⟨0|

where, |0⟩ and |1⟩ represent orthonormal states.

What are the possible measurement outcomes?

Homework Equations


[/B]
Eigenvalue Equation: A|Ψ> = a|Ψ>

The Attempt at a Solution



Apologies for the basic question but just very unsure of myself when it comes to this stuff. I have had a go and come up with a solution but I'm not sure if its right so any help would be much appreciated.

We're told that:
A = |0⟩⟨1| + |1⟩⟨0|

Can I then assume something like: Ψ = α|1> + β|0>?

using this I've then solved the eigenvalue equation, AΨ=aΨ, and found:

α|0> + β|1> = aα|1> + aβ|0>

giving:

α=aβ & β = aα

thus,

β=a2β

a = (+-) 1

hence, my eigenvalues are -1 and 1.

and these are the possible outcomes?
 
Physics news on Phys.org
You don't assume that |\psi>=\alpha |1>+ \beta |2>, there is a reason for that. The completeness relation gives,

I=|1><1|+|2><2| [look up completeness relation if you don't know about it.]

which means, |\psi>=I|\psi>=|1><1|\psi>+|2><2|\psi>

or, |\psi>=\alpha |1>+ \beta |2>,

where \alpha=<1|\psi>

and \beta=<2|\psi> are c-number.

Except that there are no more problem with your work.
 
12x4 said:

Homework Statement


A measurement is described by the operator:

|0⟩⟨1| + |1⟩⟨0|

where, |0⟩ and |1⟩ represent orthonormal states.

What are the possible measurement outcomes?

Homework Equations


[/B]
Eigenvalue Equation: A|Ψ> = a|Ψ>

The Attempt at a Solution



Apologies for the basic question but just very unsure of myself when it comes to this stuff. I have had a go and come up with a solution but I'm not sure if its right so any help would be much appreciated.

We're told that:
A = |0⟩⟨1| + |1⟩⟨0|

Can I then assume something like: Ψ = α|1> + β|0>?

using this I've then solved the eigenvalue equation, AΨ=aΨ, and found:

α|0> + β|1> = aα|1> + aβ|0>

giving:

α=aβ & β = aα

thus,

β=a2β

a = (+-) 1

hence, my eigenvalues are -1 and 1.

and these are the possible outcomes?

Yes, that looks just fine to me. The possible measurements of an experiment are the eigenvalues of the operator.
 
Last edited:
thank you. will look up the completeness relation
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K