MHB Eigenvector of 3x3 matrix with complex eigenvalues

rayne1
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Matrix A:
0 -6 10
-2 12 -20
-1 6 -10

I got the eigenvalues of: 0, 1+i, and 1-i. I can find the eigenvector of the eigenvalue 0, but for the complex eigenvalues, I keep on getting the reduced row echelon form of:
1 0 0 | 0
0 1 0 | 0
0 0 1 | 0

So, how do I find the nonzero eigenvectors of the complex eigenvalues?
 
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rayne said:
Matrix A:
0 -6 10
-2 12 -20
-1 6 -10

I got the eigenvalues of: 0, 1+i, and 1-i. I can find the eigenvector of the eigenvalue 0, but for the complex eigenvalues, I keep on getting the reduced row echelon form of:
1 0 0 | 0
0 1 0 | 0
0 0 1 | 0

So, how do I find the nonzero eigenvectors of the complex eigenvalues?

Hi rayne!

It means that 1+i and 1-i are not actually eigenvalues.
How did you conclude they were?
 
The world of 2\times 2 complex matrices is very colorful. They form a Banach-algebra, they act on spinors, they contain the quaternions, SU(2), su(2), SL(2,\mathbb C), sl(2,\mathbb C). Furthermore, with the determinant as Euclidean or pseudo-Euclidean norm, isu(2) is a 3-dimensional Euclidean space, \mathbb RI\oplus isu(2) is a Minkowski space with signature (1,3), i\mathbb RI\oplus su(2) is a Minkowski space with signature (3,1), SU(2) is the double cover of SO(3), sl(2,\mathbb C) is the...