Eigenvector of A_n: Show & Find Eigenvalue

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Homework Help Overview

The discussion revolves around demonstrating that a specific vector is an eigenvector of the matrix A_n, which is defined as an n x n matrix with all entries equal to 1. Participants are exploring the associated eigenvalue of this eigenvector.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the properties of the matrix A_n and how it relates to eigenvectors and eigenvalues. Questions about the definition of A_n and its structure are raised, along with inquiries about the implications of multiplying A_n by the vector of ones.

Discussion Status

The discussion has progressed with participants confirming that the vector [1 1 1 ...1]^T is indeed an eigenvector of A_n, with the eigenvalue being n. There is a light-hearted exchange about the simplicity of the conclusion, indicating a productive direction in understanding the concept.

Contextual Notes

Some participants express uncertainty about the topic due to it not being covered in class, and there are requests for additional resources or hints regarding the broader applications of eigenvalues and eigenvectors.

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Homework Statement



Directly show that the n x 1 vector [1 1 1 ...1]T is an eigenvector of An. What is its associated eigenvalues?

Homework Equations



N/A

The Attempt at a Solution



I started going over this topic since we did not cover it in class due to time constraints and I do not know much about it. Any additional link would be highly appreciated.
 
Last edited:
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What is [itex]A_n[/itex]?
 
Sorry, my bad. A_n is a matrix (It is pretty long and I could not write it in the forum)

A_n =
[1 . ...1]
[. . ....1]
[. . ....1] , ...
[. . ....1]
[1 1 ...1]
 
Is that supposed to be an n x n matrix with all entries equal to 1?

Suppose v is an eigenvector of A_n, what can you say about A_nv?
 
A_n is a n x n matrix with all elements 1.



A_nv = [tex]\lambda[/tex]v

where,
[tex]\lambda[/tex] = eigvenvalue
?
 
Yes. So does A_n times [1 1 1 ...1]T satisfy that condition?
 
A_n * [1 1 1 1...1]T gives [n n n n...n], doesn't it ?
 
Actually it gives [n n n n...n]T :wink:

Is that a scalar multiple of [1 1 1 1...1]T? If so, what is the eigenvalue?
 
haha, yeah right, i forgot ^T.

that is a scalar multiple of [1 1 1 1...1]^T, which means n is the associated eigenvalue. Is it that easy ?
 
  • #10
Yup :smile:

A_n [1 1 1 1...1]^T=n[1 1 1 1...1]^T, so [1 1 1 1...1]^T must be an eigenvector of A_n with eigenvalue n. Simple as that.
 
  • #11
Wow. Thanks a lot!

Could you also give me a slight hint on application of Eigenvalues and vectors?
 
  • #12
A "slight hint"? Eigenvalues and eigenvectors are used throughout mathematics. To take one simple example, "linear differential operators" are linear transformations on vector spaces of functions and solutions to linear differential equations are always based on eigenvalues and eigenvectors of the operators.

One method of determining what kinds of graphs (hyperbola, ellipse, or parabola, ...) quadratic functions give is to rewrite them as a matrix equation and find the eigenvalues (which give coefficients) and eigenvectors (which give the "principal" axes).

To find along which lines objects under stress are likely to crack first, write their "strain tensors" as matrices and find the eigenvalues and eigenvectors.
 

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