Einstein relativity between 2 coordinates systems

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The discussion revolves around calculating the speed of a moving coordinate system using the Lorentz transformation. The user initially calculated a speed of V' = 1.2 m/s but needs to find a solution of -1.2 m/s. It is clarified that the standard transformation is from the unprimed frame to the primed frame, but the user should apply the inverse transformation since the data provided is in the primed frame. This adjustment is essential to accurately determine the speed at which the two events occur at the same point in the unprimed frame. Understanding the correct application of the Lorentz transformation is crucial for solving the problem.
Atabold
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Homework Statement
Two coordinate events (24 s, 12 m) and (35 s, 25 m) occur on the x' axis of the system S'. At what speed must S' translate in order for the two events occur at the same point for S?
What is the x coordinate of this point?
Relevant Equations
V' = ( x'f — x'i ) / ( t'f — t'i )
I calculated the speed using the information provided through the above equation and finding V' = 1.2 m/s.

However, the first solution must be -1,2 m/s. I don't know how to reach it, any suggestion?
 
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Atabold said:
Homework Statement: Two coordinate events (24 s, 12 m) and (35 s, 25 m) occur on the x' axis of the system S'. At what speed must S' translate in order for the two events occur at the same point for S?
What is the x coordinate of this point?
Relevant Equations: V' = ( x'f — x'i ) / ( t'f — t'i )

I calculated the speed using the information provided through the above equation and finding V' = 1.2 m/s.

However, the first solution must be -1,2 m/s. I don't know how to reach it, any suggestion?
Are you doing the standard, conventional transformation or the inverse? Which should it be?
 
PeroK said:
Are you doing the standard, conventional transformation or the inverse? Which should it be?
I have done the Lorentz transformation
 
Atabold said:
I have done the Lorentz transformation
The usual convention for the LT is to transform from the unprimed frame to the primed frame. You need the inverse transformation here, as you have data in the primed frame.
 
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