Elastic collision, frictionless surface

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Homework Help Overview

The problem involves two air hockey pucks colliding elastically on a frictionless surface, with specific masses and initial velocities provided. The objective is to determine the final velocities of both pucks after the collision.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using conservation of momentum and conservation of energy to derive equations for the final velocities. Some express uncertainty about their approach and seek clarification on the initial steps.

Discussion Status

There is ongoing dialogue about the correct application of the conservation laws, with some participants offering guidance on setting up the equations. Multiple interpretations of how to proceed are being explored, and participants are actively engaging with each other's suggestions.

Contextual Notes

Participants mention the importance of sign conventions and the need to manage two equations with two unknowns. There is also a noted lack of confidence among some in their mathematical derivation skills.

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Homework Statement


Two air hocky pucks collide head-on elastically on a frictionless surface. The smaller puck has a mass of 0.050 kg and is moving to the right at 5.0 m/s while the larger puck has a mass of 0.10 kg and is moving to the left with a speed of 2.0 m/s. Find the velocity of each after the collision.

Homework Equations


M1V1+M2V2=M1V'1+M2V'2
.5M1V1^2+.5M2V2^2=.5M1V'1^2+.5M2V'2^2

The Attempt at a Solution


I am pretty sure I must derive an equation from conservation of momentum and conservation of energy.
 
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That would be the way to do it.

Select a positive X direction and be careful of signs.

Two equations, 2 unknowns.
 
Cant anyone help me?
 
ok, could you give me an idea of what first step I should take?
 
first I take the conservation of momentum:
M1V1+M2V2=M1V'1+M2V'2

Then I solved for V'1

V'1=(M1V1+M2V2-M2V'2)/M1
Then I substituted this for V'1 in the original equation:
M1V1+M2V2=M1[(M1V1+M2V2-M2V'2)/M1]+M2V'2

so now the only unknown variable is V'2. I have little expierence deriving equations so I am not confident this is correct. though it certainly seems to be. to me anyways.
 
My first step would be to start plugging in the values and deriving the actual equations for this situation.

With the equations in hand then solve for the 2 velocities in the usual manner.
 

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