Elastic Potential Energy problem

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Homework Help Overview

The discussion revolves around a problem involving elastic potential energy and the stretching of a spring, characterized by a force constant of 30000 N/m and a target potential energy of 47 J.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to solve for the displacement of the spring using the formula for elastic potential energy. There are discussions about the correct manipulation of the equation, particularly regarding division versus subtraction in the calculations.

Discussion Status

Participants are actively engaging with the problem, providing feedback on each other's calculations. Some guidance has been offered regarding the correct steps to take, particularly in addressing errors in the mathematical process.

Contextual Notes

There appears to be confusion regarding the manipulation of the equation, specifically in transitioning from the potential energy equation to solving for displacement. Participants are also reflecting on previous attempts and corrections made during the discussion.

kadavis2010
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Homework Statement


A spring has a force constant of 30000 N/m. How far must it be stretched for it's potential energy to be 47 J? Answer in units of m.

Homework Equations


Us= 1/2k(∆x)^2

The Attempt at a Solution


47= 1/2 (30000)(x)^2
47=15000(x)^2
-14953= x^2
√14953= 122.28
 
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kadavis2010 said:

The Attempt at a Solution


47= 1/2 (30000)(x)^2
47=15000(x)^2
So far, so good.
-14953= x^2
Oops... you subtracted instead of divided. Redo this step.
 
47= 1/2 (30000)(x)^2
47=15000(x)^2
-14953= x^2
√14953= 122.28
You subtracted when you should have divided.
 
So you are saying to do 47/15000?
that would equal .0031... then would i do the square root of it or leave it at that?

ohhh nvm i did that on one of my attempts but i forgot to put .0 in front of .0557=] Thanks a lot. I apperciate it!
 

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