Elasticity: Determine zero normal stress plane

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SUMMARY

This discussion focuses on determining the zero normal stress plane from a given stress tensor represented as T = [[2, 3, 0], [3, 2, 0], [0, 0, 5]]. The eigenvalues are identified as σ1 = σ2 = 5 and σ3 = -1. The user explores the relationship between normal stress (σ) and shear stress (τ), concluding that when σ = 0, the maximum shear stress τ can be calculated as τ = √5 using Mohr's circle. The user seeks to find the normal direction of the plane where shear stress equals √5.

PREREQUISITES
  • Understanding of stress tensors and their representation.
  • Familiarity with eigenvalues and their significance in stress analysis.
  • Knowledge of Mohr's circle for visualizing stress states.
  • Basic principles of shear and normal stress relationships.
NEXT STEPS
  • Study the derivation of normal and shear stress from stress tensors.
  • Learn how to construct and interpret Mohr's circle for different stress states.
  • Investigate the analytical methods for determining normal vectors in stress analysis.
  • Explore applications of stress analysis in material failure theories.
USEFUL FOR

Mechanical engineers, structural analysts, and students studying material mechanics who need to understand stress states and their implications in engineering applications.

Zipi Damn
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Given the stress tensor in a point, determine the zero normal stress plane.
...2 3 0
T= 3 2 0
...0 0 5
----------------------
Eigenvalues: σ1=σ2=5, σ3=-1
It must be simple, but I don't know how to determine the normal vector of that plane analytically.

I know σ=0.
t=Tn=σ+τ=τ
If normal stress σ equals zero, ¿the shear stress will be the maximum value of τ ((σ1-σ3)/2)?

Taking a look to Mohr's circle I think τ in that plane must be the intersection between the circunference and the τ axis, but that's not τmax.

I'm confused.
 
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Okay, I think I got it.

Using the equation of the mayor circunference of center (0,2) and radius R=3 from Mohr's circle, we make σ=0. Then we isolate the shear stress.

(σ-2)2+(τ-0)2=32

τ=√5

Now that I have the modulus, I want to know the normal direction of the plane in which shear stress equals √5.
 

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