Electric arc: How to calculate the required voltage for a light bow?

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SUMMARY

The required voltage to produce an electric arc between two iron nails at a distance of 3 cm is calculated using the principle of 1 kV per mm, which is derived from Paschen's Law. This means that for a gap of 30 mm (3 cm), a voltage of 30 kV is necessary to initiate the arc. Understanding this calculation is crucial for anyone working with high-voltage applications.

PREREQUISITES
  • Basic understanding of electric arcs and their properties
  • Familiarity with Paschen's Law
  • Knowledge of high-voltage safety protocols
  • Experience with electrical measurements and calculations
NEXT STEPS
  • Research Paschen's Law in detail to understand its implications in different gases
  • Explore high-voltage generation techniques and equipment
  • Learn about safety measures when working with high-voltage systems
  • Investigate the effects of atmospheric pressure on electric arc formation
USEFUL FOR

Electrical engineers, hobbyists working with high-voltage projects, and anyone interested in the principles of electric arcs and their applications.

Hans42
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<Moderator's note: Moved from a homework forum.>

Calculate the required voltage to produce a electric arc between 2 iron nails (distance: 3cm).

I´ve read in the internet that you need 1 kV per mm. But how can I calculate this value, that I need 1kV per 1mm?
 
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Hans42 said:
<Moderator's note: Moved from a homework forum.>

Calculate the required voltage to produce a electric arc between 2 iron nails (distance: 3cm).

I´ve read in the internet that you need 1 kV per mm. But how can I calculate this value, that I need 1kV per 1mm?
Welcome to the PF. :smile:

See if this helps: https://en.wikipedia.org/wiki/Paschen's_law

What is your background in working with high voltages?
 

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