Electric Current in Moving Plate Capacitor with Velocity 6 m/s and U=600 V

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Homework Help Overview

The problem involves a thin parallel plate capacitor connected to a 600 V current source, with one electrode being pulled at a velocity of 6 m/s. The dimensions of the electrodes are specified, and the task is to determine the electric current flowing in the circuit.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between charge, capacitance, and current, with attempts to express charge in terms of capacitance equations. Questions arise regarding the time dependence of the current and whether a constant value can be determined.

Discussion Status

Some participants have provided guidance on exploring the time dependence of the current and have noted that the current is not constant. There is an ongoing exploration of how to express current in relation to the changing conditions of the capacitor.

Contextual Notes

Participants are considering the implications of the velocity of the moving electrode and its effect on capacitance and current. There is a suggestion to clarify the terminology used regarding the voltage source.

Noirro
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Homework Statement


Thin parallel plate capacitor is connected to a U=600 V current source. Find the electric current flowing in the circuit if one of the electrodes is pulled at v=6 m/s velocity. The electrodes are square (l=10 cm), the distance between them is d=1 mm.

Homework Equations


C=ε0\frac{A}{d+vt}, C=\frac{q}{U}, I=\frac{dq}{dt}

The Attempt at a Solution


I tried finding the current by first expressing q from those capacitor equations and plugging it into the dq/dt equation, but there is still time t left. I am not sure if the answer depends on time or is it possible to find some constant value of I?
 
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Noirro said:

Homework Statement


Thin parallel plate capacitor is connected to a U=600 V current source. Find the electric current flowing in the circuit if one of the electrodes is pulled at v=6 m/s velocity. The electrodes are square (l=10 cm), the distance between them is d=1 mm.

Homework Equations


C=ε0\frac{A}{d+vt}, C=\frac{q}{U}, I=\frac{dq}{dt}

The Attempt at a Solution


I tried finding the current by first expressing q from those capacitor equations and plugging it into the dq/dt equation, but there is still time t left. I am not sure if the answer depends on time or is it possible to find some constant value of I?

No, the current is not constant. Find the time dependence of the current, and the current at t=0.

ehild
 
ehild said:
No, the current is not constant. Find the time dependence of the current, and the current at t=0.

ehild

OK thanks!
 
Thin parallel plate capacitor is connected to a U=600 V current source

I assume you mean a voltage source.
 
Hint: i = C dV/dt is not the complete story.

The complete story is i = d/dt (CV).
 

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