Electric Dipole Moment Vector Calculation

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SUMMARY

The discussion focuses on calculating the electric dipole moment vector for a system of two point charges, each with a magnitude of 1.90e-6 C, positioned at (1.50, 1.50) mm and (−1.50, −1.50) mm. The dipole moment (p) is determined using the formula p = qd, where d is the distance between the charges, calculated as d = sqrt(x^2 + y^2). The correct calculation yields a dipole moment of approximately 4.03051e-9 C·m.

PREREQUISITES
  • Understanding of electric charge and dipole moment concepts
  • Familiarity with the formula p = qd
  • Basic knowledge of coordinate geometry
  • Ability to perform square root calculations
NEXT STEPS
  • Review the concept of electric dipole moments in electrostatics
  • Learn about the significance of dipole moments in molecular chemistry
  • Explore the implications of dipole moments in electric fields
  • Practice calculating dipole moments with varying charge configurations
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Students studying electromagnetism, physicists, and anyone interested in understanding electric dipole moments and their applications in physics and chemistry.

lacar213
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Homework Statement


Two opposite point charges of magnitude 1.90e-6 C are located near the origin. The positive charge is at (1.50, 1.50) mm and the negative charge is at (−1.50, −1.50) mm. What is the magnitude of the dipole moment vector for this pair of charges?


Homework Equations


p = qd
d = sqrt(x^2 + y^2)


The Attempt at a Solution


I solved d = .002121
solved p = 4.03051e.9
 
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Try calculating d again. It's the distance between the two charges.

Also, including units with the values would be a good habit to get into.
 

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